10b^2=-10b+4

Solution for 10b^2=-10b+4 equation:

10b^2=-10b+4

We move all terms to the left:

10b^2-(-10b+4)=0

We get rid of parentheses

10b^2+10b-4=0

a = 10; b = 10; c = -4;
Δ = b2-4ac
Δ = 102-4·10·(-4)
Δ = 260
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{260}=\sqrt{4*65}=\sqrt{4}*\sqrt{65}=2\sqrt{65}$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-2\sqrt{65}}{2*10}=\frac{-10-2\sqrt{65}}{20}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+2\sqrt{65}}{2*10}=\frac{-10+2\sqrt{65}}{20}
$